# fizz_array



**Requirements:**
```eval_rst
- :ref:`fundamentals:list building and filtering`

```


Given a number `n`, create and return a new int list of length `n`, containing the numbers `0, 1, 2, ... n-1`. The given `n` may be `0`, in which case just return a length `0` list. You do not need a separate if-statement for the length-0 case; the for-loop should naturally execute `0` times in that case, so it just works.

```
fizzList(4) -> [0, 1, 2, 3]
fizzList(1) -> [0]
fizzList(10) -> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
```

This exercise was taken from [codingbat.com](https://codingbat.com/prob/p180920) and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

## Starter Code
```python
from typing import List


def fizz_array(n: int) -> List[int]:
    pass


result = fizz_array(4)
print(result)
```

## Tests
```python
from main import fizz_array


def test_fizz_array_1():
    assert fizz_array(4) == [0, 1, 2, 3]


def test_fizz_array_2():
    assert fizz_array(1) == [0]


def test_fizz_array_3():
    assert fizz_array(10) == [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]


def test_fizz_array_4():
    assert fizz_array(0) == []


def test_fizz_array_5():
    assert fizz_array(2) == [0, 1]


def test_fizz_array_6():
    assert fizz_array(7) == [0, 1, 2, 3, 4, 5, 6]
```