# see_color Given a string, if the string begins with "red" or "blue" return that color string, otherwise return the empty string. ``` see_color("redxx") -> "red" see_color("xxred") -> "" see_color("blueTimes") -> "blue" ``` This exercise was taken from [codingbat.com](https://codingbat.com/prob/p199216) and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java. ## Starter Code ```python def see_color(string: str) -> str: pass result = see_color('redxx') print(result) ``` ## Tests ```python from main import see_color def test_see_color_1(): assert see_color('redxx') == 'red' def test_see_color_2(): assert see_color('xxred') == '' def test_see_color_3(): assert see_color('blueTimes') == 'blue' def test_see_color_4(): assert see_color('NoColor') == '' def test_see_color_5(): assert see_color('red') == 'red' def test_see_color_6(): assert see_color('re') == '' def test_see_color_7(): assert see_color('blu') == '' def test_see_color_8(): assert see_color('blue') == 'blue' def test_see_color_9(): assert see_color('a') == '' def test_see_color_10(): assert see_color('') == '' def test_see_color_11(): assert see_color('xyzred') == '' ```