bunny_ears_2

We have bunnies standing in a line, numbered 1, 2, … The odd bunnies (1, 3, ..) have the normal 2 ears. The even bunnies (2, 4, ..) we’ll say have 3 ears, because they each have a raised foot. Recursively return the number of “ears” in the bunny line 1, 2, … n (without loops or multiplication).

bunny_ears_2(0) -> 0
bunny_ears_2(1) -> 2
bunny_ears_2(2) -> 5

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def bunny_ears_2(bunnies: int) -> int:
    pass


result = bunny_ears_2(0)
print(result)

Tests

from main import bunny_ears_2


def test_bunny_ears_2_1():
    assert bunny_ears_2(0) == 0


def test_bunny_ears_2_2():
    assert bunny_ears_2(1) == 2


def test_bunny_ears_2_3():
    assert bunny_ears_2(2) == 5


def test_bunny_ears_2_4():
    assert bunny_ears_2(3) == 7


def test_bunny_ears_2_5():
    assert bunny_ears_2(4) == 10


def test_bunny_ears_2_6():
    assert bunny_ears_2(5) == 12


def test_bunny_ears_2_7():
    assert bunny_ears_2(6) == 15


def test_bunny_ears_2_8():
    assert bunny_ears_2(10) == 25