has_bad

Given a string, return true if “bad” appears starting at index 0 or 1 in the string, such as with “badxxx” or “xbadxx” but not “xxbadxx”. The string may be any length, including 0. Note: use .equals() to compare 2 strings.

has_bad("badxx") -> true
has_bad("xbadxx") -> true
has_bad("xxbadxx") -> false

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def has_bad(string: str) -> bool:
    pass


result = has_bad('badxx')
print(result)

Tests

from main import has_bad


def test_has_bad_1():
    assert has_bad('badxx') == True


def test_has_bad_2():
    assert has_bad('xbadxx') == True


def test_has_bad_3():
    assert has_bad('xxbadxx') == False


def test_has_bad_4():
    assert has_bad('code') == False


def test_has_bad_5():
    assert has_bad('bad') == True


def test_has_bad_6():
    assert has_bad('ba') == False


def test_has_bad_7():
    assert has_bad('xba') == False


def test_has_bad_8():
    assert has_bad('xbad') == True


def test_has_bad_9():
    assert has_bad('') == False


def test_has_bad_10():
    assert has_bad('badyy') == True