without_x_2

Given a string, if one or both of the first 2 chars is ‘x’, return the string without those ‘x’ chars, and otherwise return the string unchanged. This is a little harder than it looks.

without_x_2("xHi") -> "Hi"
without_x_2("Hxi") -> "Hi"
without_x_2("Hi") -> "Hi"

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def without_x_2(string: str) -> str:
    pass


result = without_x_2('xHi')
print(result)

Tests

from main import without_x_2


def test_without_x_2_1():
    assert without_x_2('xHi') == 'Hi'


def test_without_x_2_2():
    assert without_x_2('Hxi') == 'Hi'


def test_without_x_2_3():
    assert without_x_2('Hi') == 'Hi'


def test_without_x_2_4():
    assert without_x_2('xxHi') == 'Hi'


def test_without_x_2_5():
    assert without_x_2('Hix') == 'Hix'


def test_without_x_2_6():
    assert without_x_2('xaxb') == 'axb'


def test_without_x_2_7():
    assert without_x_2('xx') == ''


def test_without_x_2_8():
    assert without_x_2('x') == ''


def test_without_x_2_9():
    assert without_x_2('') == ''


def test_without_x_2_10():
    assert without_x_2('Hello') == 'Hello'


def test_without_x_2_11():
    assert without_x_2('Hexllo') == 'Hexllo'


def test_without_x_2_12():
    assert without_x_2('xHxllo') == 'Hxllo'