bob_there

Requirements:

• access a single character

• if, else

• loop through a string (while)

• returning a value

Return true if the given string contains a “bob” string, but where the middle ‘o’ char can be any char.

bob_there("abcbob") -> true
bob_there("b9b") -> true
bob_there("bac") -> false

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def bob_there(string: str) -> bool:
    pass


result = bob_there('abcbob')
print(result)

Tests

from main import bob_there


def test_bob_there_1():
    assert bob_there('abcbob') == True


def test_bob_there_2():
    assert bob_there('b9b') == True


def test_bob_there_3():
    assert bob_there('bac') == False


def test_bob_there_4():
    assert bob_there('bbb') == True


def test_bob_there_5():
    assert bob_there('abcdefb') == False


def test_bob_there_6():
    assert bob_there('123abcbcdbabxyz') == True


def test_bob_there_7():
    assert bob_there('b12') == False


def test_bob_there_8():
    assert bob_there('b1b') == True


def test_bob_there_9():
    assert bob_there('b12b1b') == True


def test_bob_there_10():
    assert bob_there('bbc') == False


def test_bob_there_11():
    assert bob_there('bbb') == True


def test_bob_there_12():
    assert bob_there('bb') == False


def test_bob_there_13():
    assert bob_there('b') == False