xyz_there

Requirements:

• substrings and slicing

• if, else

• loop through a string (while)

• returning a value

Return true if the given string contains an appearance of “xyz” where the xyz is not directly preceeded by a period (.). So “xxyz” counts but “x.xyz” does not.

xyz_there("abcxyz") -> true
xyz_there("abc.xyz") -> false
xyz_there("xyz.abc") -> true

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def xyz_there(string: str) -> bool:
    pass


result = xyz_there('abcxyz')
print(result)

Tests

from main import xyz_there


def test_xyz_there_1():
    assert xyz_there('abcxyz') == True


def test_xyz_there_2():
    assert xyz_there('abc.xyz') == False


def test_xyz_there_3():
    assert xyz_there('xyz.abc') == True


def test_xyz_there_4():
    assert xyz_there('abcxy') == False


def test_xyz_there_5():
    assert xyz_there('xyz') == True


def test_xyz_there_6():
    assert xyz_there('xy') == False


def test_xyz_there_7():
    assert xyz_there('x') == False


def test_xyz_there_8():
    assert xyz_there('') == False


def test_xyz_there_9():
    assert xyz_there('abc.xyzxyz') == True


def test_xyz_there_10():
    assert xyz_there('abc.xxyz') == True


def test_xyz_there_11():
    assert xyz_there('.xyz') == False


def test_xyz_there_12():
    assert xyz_there('12.xyz') == False


def test_xyz_there_13():
    assert xyz_there('12xyz') == True


def test_xyz_there_14():
    assert xyz_there('1.xyz.xyz2.xyz') == False