repeat_front

Requirements:

• substrings and slicing

• loop with a counter variable

• string building and filtering

• returning a value

Given a string and an int n, return a string made of the first n characters of the string, followed by the first n-1 characters of the string, and so on. You may assume that n is between 0 and the length of the string, inclusive (i.e. n >= 0 and n <= str.length()).

repeat_front("Chocolate", 4) -> "ChocChoChC"
repeat_front("Chocolate", 3) -> "ChoChC"
repeat_front("Ice Cream", 2) -> "IcI"

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def repeat_front(string: str, n: int) -> str:
    pass


result = repeat_front('Chocolate', 4)
print(result)

Tests

from main import repeat_front


def test_repeat_front_1():
    assert repeat_front('Chocolate', 4) == 'ChocChoChC'


def test_repeat_front_2():
    assert repeat_front('Chocolate', 3) == 'ChoChC'


def test_repeat_front_3():
    assert repeat_front('Ice Cream', 2) == 'IcI'


def test_repeat_front_4():
    assert repeat_front('Ice Cream', 1) == 'I'


def test_repeat_front_5():
    assert repeat_front('Ice Cream', 0) == ''


def test_repeat_front_6():
    assert repeat_front('xyz', 3) == 'xyzxyx'


def test_repeat_front_7():
    assert repeat_front('', 0) == ''


def test_repeat_front_8():
    assert repeat_front('Java', 4) == 'JavaJavJaJ'


def test_repeat_front_9():
    assert repeat_front('Java', 1) == 'J'