diff_21

Given an int n, return the absolute difference between n and 21, except return double the absolute difference if n is over 21.

diff_21(19) -> 2
diff_21(10) -> 11
diff_21(21) -> 0

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def diff_21(n: int) -> int:
    pass


result = diff_21(19)
print(result)

Tests

from main import diff_21


def test_diff_21_1():
    assert diff_21(19) == 2


def test_diff_21_2():
    assert diff_21(10) == 11


def test_diff_21_3():
    assert diff_21(21) == 0


def test_diff_21_4():
    assert diff_21(22) == 2


def test_diff_21_5():
    assert diff_21(25) == 8


def test_diff_21_6():
    assert diff_21(30) == 18


def test_diff_21_7():
    assert diff_21(0) == 21


def test_diff_21_8():
    assert diff_21(1) == 20


def test_diff_21_9():
    assert diff_21(2) == 19


def test_diff_21_10():
    assert diff_21(-1) == 22


def test_diff_21_11():
    assert diff_21(-2) == 23


def test_diff_21_12():
    assert diff_21(50) == 58