every_nth

Given a non-empty string and an int N, return the string made starting with char 0, and then every Nth char of the string. So if N is 3, use char 0, 3, 6, … and so on. N is 1 or more.

every_nth("Miracle", 2) -> "Mrce"
every_nth("abcdefg", 2) -> "aceg"
every_nth("abcdefg", 3) -> "adg"

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

def every_nth(string: str, n: int) -> str:
    pass


result = every_nth('Miracle', 2)
print(result)

Tests

from main import every_nth


def test_every_nth_1():
    assert every_nth('Miracle', 2) == 'Mrce'


def test_every_nth_2():
    assert every_nth('abcdefg', 2) == 'aceg'


def test_every_nth_3():
    assert every_nth('abcdefg', 3) == 'adg'


def test_every_nth_4():
    assert every_nth('Chocolate', 3) == 'Cca'


def test_every_nth_5():
    assert every_nth('Chocolates', 3) == 'Ccas'


def test_every_nth_6():
    assert every_nth('Chocolates', 4) == 'Coe'


def test_every_nth_7():
    assert every_nth('Chocolates', 100) == 'C'