common_end

Requirements:

• if, elif, else

• accessing list elements

Given 2 lists of ints, a and b, return true if they have the same first element or they have the same last element. Both lists will be length 1 or more.

common_end([1, 2, 3], [7, 3]) -> true
common_end([1, 2, 3], [7, 3, 2]) -> false
common_end([1, 2, 3], [1, 3]) -> true

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def common_end(a: List[int], b: List[int]) -> bool:
    pass


result = common_end([1, 2, 3], [7, 3])
print(result)

Tests

from main import common_end


def test_common_end_1():
    assert common_end([1, 2, 3], [7, 3]) == True


def test_common_end_2():
    assert common_end([1, 2, 3], [7, 3, 2]) == False


def test_common_end_3():
    assert common_end([1, 2, 3], [1, 3]) == True


def test_common_end_4():
    assert common_end([1, 2, 3], [1]) == True


def test_common_end_5():
    assert common_end([1, 2, 3], [2]) == False