double_23

Given an int list, return true if the list contains 2 twice, or 3 twice. The list will be length 0, 1, or 2.

double_23([2, 2]) -> true
double_23([3, 3]) -> true
double_23([2, 3]) -> false

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def double_23(nums: List[int]) -> bool:
    pass


result = double_23([2, 2])
print(result)

Tests

from main import double_23


def test_double_23_1():
    assert double_23([2, 2]) == True


def test_double_23_2():
    assert double_23([3, 3]) == True


def test_double_23_3():
    assert double_23([2, 3]) == False


def test_double_23_4():
    assert double_23([3, 2]) == False


def test_double_23_5():
    assert double_23([4, 5]) == False


def test_double_23_6():
    assert double_23([2]) == False


def test_double_23_7():
    assert double_23([3]) == False


def test_double_23_8():
    assert double_23([]) == False


def test_double_23_9():
    assert double_23([3, 4]) == False