rotate_left_3

Given a list of ints length 3, return a list with the elements “rotated left” so [1, 2, 3] yields [2, 3, 1].

rotate_left_3([1, 2, 3]) -> [2, 3, 1]
rotate_left_3([5, 11, 9]) -> [11, 9, 5]
rotate_left_3([7, 0, 0]) -> [0, 0, 7]

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def rotate_left_3(nums: List[int]) -> List[int]:
    pass


result = rotate_left_3([1, 2, 3])
print(result)

Tests

from main import rotate_left_3


def test_rotate_left_3_1():
    assert rotate_left_3([1, 2, 3]) == [2, 3, 1]


def test_rotate_left_3_2():
    assert rotate_left_3([5, 11, 9]) == [11, 9, 5]


def test_rotate_left_3_3():
    assert rotate_left_3([7, 0, 0]) == [0, 0, 7]


def test_rotate_left_3_4():
    assert rotate_left_3([1, 2, 1]) == [2, 1, 1]


def test_rotate_left_3_5():
    assert rotate_left_3([0, 0, 1]) == [0, 1, 0]