no_23

Given an int list length 2, return true if it does not contain a 2 or 3.

no_23([4, 5]) -> true
no_23([4, 2]) -> false
no_23([3, 5]) -> false

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def no_23(nums: List[int]) -> bool:
    pass


result = no_23([4, 5])
print(result)

Tests

from main import no_23


def test_no_23_1():
    assert no_23([4, 5]) == True


def test_no_23_2():
    assert no_23([4, 2]) == False


def test_no_23_3():
    assert no_23([3, 5]) == False


def test_no_23_4():
    assert no_23([1, 9]) == True


def test_no_23_5():
    assert no_23([2, 9]) == False


def test_no_23_6():
    assert no_23([1, 3]) == False


def test_no_23_7():
    assert no_23([1, 1]) == True


def test_no_23_8():
    assert no_23([2, 2]) == False


def test_no_23_9():
    assert no_23([3, 3]) == False


def test_no_23_10():
    assert no_23([7, 8]) == True


def test_no_23_11():
    assert no_23([8, 7]) == True