fix_23

Given an int list length 3, if there is a 2 in the list immediately followed by a 3, set the 3 element to 0. Return the changed list.

fix_23([1, 2, 3]) -> [1, 2, 0]
fix_23([2, 3, 5]) -> [2, 0, 5]
fix_23([1, 2, 1]) -> [1, 2, 1]

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def fix_23(nums: List[int]) -> List[int]:
    pass


result = fix_23([1, 2, 3])
print(result)

Tests

from main import fix_23


def test_fix_23_1():
    assert fix_23([1, 2, 3]) == [1, 2, 0]


def test_fix_23_2():
    assert fix_23([2, 3, 5]) == [2, 0, 5]


def test_fix_23_3():
    assert fix_23([1, 2, 1]) == [1, 2, 1]


def test_fix_23_4():
    assert fix_23([3, 2, 1]) == [3, 2, 1]


def test_fix_23_5():
    assert fix_23([2, 2, 3]) == [2, 2, 0]


def test_fix_23_6():
    assert fix_23([2, 3, 3]) == [2, 0, 3]