big_diff

Requirements:

• loop through a list (for)

• if, elif, else

Given a list length 1 or more of ints, return the difference between the largest and smallest values in the list. Note: In the spirit of practice, do not use the built-in min() and max() functions use a loop to discover the largest and smallest values.

big_diff([10, 3, 5, 6]) -> 7
big_diff([7, 2, 10, 9]) -> 8
big_diff([2, 10, 7, 2]) -> 8

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def big_diff(nums: List[int]) -> int:
    pass


result = big_diff([10, 3, 5, 6])
print(result)

Tests

from main import big_diff


def test_big_diff_1():
    assert big_diff([10, 3, 5, 6]) == 7


def test_big_diff_2():
    assert big_diff([7, 2, 10, 9]) == 8


def test_big_diff_3():
    assert big_diff([2, 10, 7, 2]) == 8


def test_big_diff_4():
    assert big_diff([2, 10]) == 8


def test_big_diff_5():
    assert big_diff([10, 2]) == 8


def test_big_diff_6():
    assert big_diff([10, 0]) == 10


def test_big_diff_7():
    assert big_diff([2, 3]) == 1


def test_big_diff_8():
    assert big_diff([2, 2]) == 0


def test_big_diff_9():
    assert big_diff([2]) == 0


def test_big_diff_10():
    assert big_diff([5, 1, 6, 1, 9, 9]) == 8


def test_big_diff_11():
    assert big_diff([7, 6, 8, 5]) == 3


def test_big_diff_12():
    assert big_diff([7, 7, 6, 8, 5, 5, 6]) == 3