post_4

Given a non-empty list of ints, return a new list containing the elements from the original list that come after the last 4 in the original list. The original list will contain at least one 4. Note that it is valid in java to create a list of length 0.

post_4([2, 4, 1, 2]) -> [1, 2]
post_4([4, 1, 4, 2]) -> [2]
post_4([4, 4, 1, 2, 3]) -> [1, 2, 3]

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def post_4(nums: List[int]) -> List[int]:
    pass


result = post_4([2, 4, 1, 2])
print(result)

Tests

from main import post_4


def test_post_4_1():
    assert post_4([2, 4, 1, 2]) == [1, 2]


def test_post_4_2():
    assert post_4([4, 1, 4, 2]) == [2]


def test_post_4_3():
    assert post_4([4, 4, 1, 2, 3]) == [1, 2, 3]


def test_post_4_4():
    assert post_4([4, 2]) == [2]


def test_post_4_5():
    assert post_4([4, 4, 3]) == [3]


def test_post_4_6():
    assert post_4([4, 4]) == []


def test_post_4_7():
    assert post_4([4]) == []


def test_post_4_8():
    assert post_4([2, 4, 1, 4, 3, 2]) == [3, 2]


def test_post_4_9():
    assert post_4([4, 1, 4, 2, 2, 2]) == [2, 2, 2]


def test_post_4_10():
    assert post_4([3, 4, 3, 2]) == [3, 2]