ten_run

For each multiple of 10 in the given list, change all the values following it to be that multiple of 10, until encountering another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}.

ten_run([2, 10, 3, 4, 20, 5]) -> [2, 10, 10, 10, 20, 20]
ten_run([10, 1, 20, 2]) -> [10, 10, 20, 20]
ten_run([10, 1, 9, 20]) -> [10, 10, 10, 20]

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def ten_run(nums: List[int]) -> List[int]:
    pass


result = ten_run([2, 10, 3, 4, 20, 5])
print(result)

Tests

from main import ten_run


def test_ten_run_1():
    assert ten_run([2, 10, 3, 4, 20, 5]) == [2, 10, 10, 10, 20, 20]


def test_ten_run_2():
    assert ten_run([10, 1, 20, 2]) == [10, 10, 20, 20]


def test_ten_run_3():
    assert ten_run([10, 1, 9, 20]) == [10, 10, 10, 20]


def test_ten_run_4():
    assert ten_run([1, 2, 50, 1]) == [1, 2, 50, 50]


def test_ten_run_5():
    assert ten_run([1, 20, 50, 1]) == [1, 20, 50, 50]


def test_ten_run_6():
    assert ten_run([10, 10]) == [10, 10]


def test_ten_run_7():
    assert ten_run([10, 2]) == [10, 10]


def test_ten_run_8():
    assert ten_run([0, 2]) == [0, 0]


def test_ten_run_9():
    assert ten_run([1, 2]) == [1, 2]


def test_ten_run_10():
    assert ten_run([1]) == [1]


def test_ten_run_11():
    assert ten_run([]) == []