fizz_array

Requirements:

• list building and filtering

Given a number n, create and return a new int list of length n, containing the numbers 0, 1, 2, ... n-1. The given n may be 0, in which case just return a length 0 list. You do not need a separate if-statement for the length-0 case; the for-loop should naturally execute 0 times in that case, so it just works.

fizzList(4) -> [0, 1, 2, 3]
fizzList(1) -> [0]
fizzList(10) -> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def fizz_array(n: int) -> List[int]:
    pass


result = fizz_array(4)
print(result)

Tests

from main import fizz_array


def test_fizz_array_1():
    assert fizz_array(4) == [0, 1, 2, 3]


def test_fizz_array_2():
    assert fizz_array(1) == [0]


def test_fizz_array_3():
    assert fizz_array(10) == [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]


def test_fizz_array_4():
    assert fizz_array(0) == []


def test_fizz_array_5():
    assert fizz_array(2) == [0, 1]


def test_fizz_array_6():
    assert fizz_array(7) == [0, 1, 2, 3, 4, 5, 6]