count_evens

Requirements:

• mathematical operations

• loop through a list (for)

• loop with an accumulator variable

Return the number of even ints in the given list. Note: the % “mod” operator computes the remainder, e.g. 5 % 2 is 1.

count_evens([2, 1, 2, 3, 4]) -> 3
count_evens([2, 2, 0]) -> 3
count_evens([1, 3, 5]) -> 0

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def count_evens(nums: List[int]) -> int:
    pass


result = count_evens([2, 1, 2, 3, 4])
print(result)

Tests

from main import count_evens


def test_count_evens_1():
    assert count_evens([2, 1, 2, 3, 4]) == 3


def test_count_evens_2():
    assert count_evens([2, 2, 0]) == 3


def test_count_evens_3():
    assert count_evens([1, 3, 5]) == 0


def test_count_evens_4():
    assert count_evens([]) == 0


def test_count_evens_5():
    assert count_evens([11, 9, 0, 1]) == 1


def test_count_evens_6():
    assert count_evens([2, 11, 9, 0]) == 2


def test_count_evens_7():
    assert count_evens([2]) == 1


def test_count_evens_8():
    assert count_evens([2, 5, 12]) == 2