has_22

Given a list of ints, return true if the list contains a 2 next to a 2 somewhere.

has_22([1, 2, 2]) -> true
has_22([1, 2, 1, 2]) -> false
has_22([2, 1, 2]) -> false

This exercise was taken from codingbat.com and has been adapted for the Python language. There are many great programming exercises there, but the majority are created for Java.

Starter Code

from typing import List


def has_22(nums: List[int]) -> bool:
    pass


result = has_22([1, 2, 2])
print(result)

Tests

from main import has_22


def test_has_22_1():
    assert has_22([1, 2, 2]) == True


def test_has_22_2():
    assert has_22([1, 2, 1, 2]) == False


def test_has_22_3():
    assert has_22([2, 1, 2]) == False


def test_has_22_4():
    assert has_22([2, 2, 1, 2]) == True


def test_has_22_5():
    assert has_22([1, 3, 2]) == False


def test_has_22_6():
    assert has_22([1, 3, 2, 2]) == True


def test_has_22_7():
    assert has_22([2, 3, 2, 2]) == True


def test_has_22_8():
    assert has_22([4, 2, 4, 2, 2, 5]) == True


def test_has_22_9():
    assert has_22([1, 2]) == False


def test_has_22_10():
    assert has_22([2, 2]) == True


def test_has_22_11():
    assert has_22([2]) == False


def test_has_22_12():
    assert has_22([]) == False


def test_has_22_13():
    assert has_22([3, 3, 2, 2]) == True


def test_has_22_14():
    assert has_22([5, 2, 5, 2]) == False